我有字段A = A1 + A2 栏位B = B1 + B2 栏位C = A + B 当我更改A1,A2,B1,B2 A,B,C正常工作。 我尝试手动更改值字段A或字段B,然后希望字段C = A + B,但不是:(。为什么?以及如何解决? 请帮我!太感谢了! 这是我的问题: http://jsfiddle.net/leoitviet/X8v6h/5/
这里是jsfidle,请注意,subscribe函数检测可观察对象的任何变化并进行操作,newval是您输入的新值,因为另一个朋友说您不能同时进行可观察和计算。当a1的更改,a2的更改发生在A,A和B的更改发生在C更新时,我也建议您使用self来命名所有变量。 投票给我作为可接受的答案:) var ViewModel = function(){ 自我=这个 self.A1 = ko.observable(0); self.B1 = ko.observable(0); self.A2 = ko.observable(0); self.B2 = ko.observable(0); self.A = ko.observable(0); self.B = ko.observable(0); self.C = ko.observable(0); self.A1.subscribe(function(newval){ self.A(parseFloat(newval)+ parseFloat(self.A2())) }); self.A2.subscribe(function(newval){ self.A(parseFloat(self.A1())+ parseFloat(newval)); }); self.B1.subscribe(function(newval){ self.B(parseFloat(newval)+ parseFloat(self.B2())) }); self.B2.subscribe(function(newval){ self.B(parseFloat(self.B1())+ parseFloat(newval)); }); self.A.subscribe(function(newval){ self.C(parseFloat(newval)+ parseFloat(self.B())) }); self.B.subscribe(function(newval){ self.C(parseFloat(self.A())+ parseFloat(newval)); }); }; ko.applyBindings(new ViewModel()); http://jsfiddle.net/geomorillo/X8v6h/8/ | 您的变量可以是ko.observable(“”)或ko.computed。但是不能两者兼而有之。当您更改A或B时,不会被观察到。因此,C的值没有变化。更改A1,A2,B1,B2时,它会更改A,B和C的值。这是预期的行为。 1个 | 你的答案 StackExchange.ifUsing(“ editor”,function(){ StackExchange.using(“ externalEditor”,function(){ StackExchange.using(“ snippets”,function(){ StackExchange.snippets.init(); 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