我有一堆未排序的項目和一堆比較器。 我想通過使用“ thenComparing”(Multisort)將所有比較器應用於流 除了下面的代碼,還有沒有比這更優雅的方法了? 流未排序= ...; Stream比較器= ...; 比較器compareFunc = compares.reduce(null,(a,b)-> { if(a == null){ 返回b; }別的 { 返回a.thenComparing(b); } }); 流結果= unsorted.sorted(compareFunc);
不要為比較器使用身份值。如果比較器流為空(即不包含任何比較器),則不應排序: 流結果= comparators.reduce(Comparator :: thenComparing) .map(unsorted :: sorted).ElElse(unsorted); 請注意,如果比較器流僅包含一個Comparator,則該Comparator將是縮減的結果。 傳遞給Optional.map的方法參考可能需要一些經驗來習慣它。因此,可能值得使用更詳細的lambda語法來顯示發生了什麼: Streamresult = comparators.reduce(Comparator :: thenComparing) .map((comparator)-> unsorted.sorted(comparator))。orElse(unsorted); 這是編程風格或個人喜好問題,可能會隨著時間而改變。 1個 | 使用Mark Peters的建議並將其與方法引用混合,您可以通過以下方式編寫比較器: 比較器compareFunc = compares.reduce((a,b)-> 0,Comparator :: thenComparing); 或者從Holger竊取一些信息: 可選的 compareFunc = compares.reduce(Comparator :: thenComparing); Stream <?>結果= compareFunc.isPresent()? result.sorted(compareFunc.get()) :未分類; 2個 | 你的答案 StackExchange.ifUsing(“ editor”,function(){ StackExchange.using(“ externalEditor”,function(){ StackExchange.using(“ snippets”,function(){ StackExchange.snippets.init(); }); }); },“代碼段”); StackExchange.ready(function(){ var channelOptions = { 標籤:“” .split(“”), id:“ 1” }; initTagRenderer(“”。split(“”),“” .split(“”),channelOptions); 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