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我有一個巨大的文本文件,僅需複制某些行即可。我已經為它寫了一個蝙蝠腳本。我瀏覽文本文件,僅考慮以“ ResponseCode”為前綴的那些行。 bat文件如下:
@ECHO OFF和setlocal enabledelayedexpansion
如果存在E:\ output.txt刪除E:\ output.txt
為(E:\ test.txt)中的/ f“ delims =” %% i
設置“ line0 = %% i”
設置“ line =!line0:* ResponseCode =!”
如果不是“!line0!” ==“!line!” (
對於(“!line!”)中的/ f %% j,請設置“ line = %% j”
如果未定義$ a!line! (
設置“ $ a!line!=!line!”
(echo(!line0!)>> E:\ output.txt
)
)
)
但是,當我運行上述腳本時,它僅從test.txt複製一行而不是按預期復制四行並將其寫入output.txt。如何使其複制包含ResponseCode作為前綴詞的所有四行? 
findstr / L“ ResponseCode”“ E:\ test.txt”將返回字面上包含ResponseCode的所有行。
通過添加>>“ E:\ output.txt”,可以輕鬆地將返回的行重定向到您的輸出文件。
以下代碼解析findstr的輸出,並在ResponseCode之後輸出所有內容:
setlocal EnableDelayedExpansion
收件人。>“ E:\ output.txt”
為/ F“ delims =” %% L in('findstr / L“ ResponseCode”“ E:\ test.txt”')執行(
設置“ LINE = %% L”並設置“ LINE =!LINE:* ResponseCode =!” &迴聲!LINE!
)>>“ E:\ output.txt”
本地
請注意,由於未給出/ I,因此findstr執行區分大小寫的搜索;但是,以不區分大小寫的方式刪除(首次)出現的ResponseCode(通過擴展!LINE:* ResponseCode =!)中的所有內容!
|
你能代替嗎?
findstr / b ResponseCode“ E:\ test.txt” >>“ E:\ output.txt”
/ b告訴它僅在行的開頭存在“ ResponseCode”的情況下才輸出該行。
|
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